Calling Java Serialized Object from JSP
This article is an answer for my simple assignment i created several weeks ago for my friend, Zainul Iman. Its about creating a simple web application that can persist and retrieve values by putting it values on a java object and serialized it on a plain text file.
Okay, so basically i only create 4 files. Only 1 java files, 2 jsp and 1 servlet. And only adding several lines on web.xml file.
First is a simple java bean to store my inserted value,
package com.edw.bean;
import java.io.Serializable;
public class Student implements Serializable{
private String name;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
And a simple jsp file to serve as view layer, in here user can insert value which will be persist on java bean.
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert Value</title>
</head>
<body>
<form method="post" action="StudentServlet">
<table>
<tr>
<td>Insert Name : </td>
<td><input type="text" name="name" /> </td>
</tr>
<tr>
<td colspan="2"><input type="submit" /></td>
</tr>
</table>
</form>
</body>
</html>
This is my servlet class, in this class i handle the serialization of the inserted value into java object
package com.edw.servlet;
import com.edw.bean.Student;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class StudentServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
String name = request.getParameter("name");
Student student = new Student();
student.setName(name);
FileOutputStream fileOutputStream2 = new FileOutputStream(new File("D:\\test12.txt"), false);
ObjectOutputStream objectOutputStream = new ObjectOutputStream(fileOutputStream2);
objectOutputStream.writeObject(student);
response.getWriter().println("Success....!!");
response.getWriter().println("list of student ---> <a href=\"\">daftar.jsp</a>");
}
}
And the serialized object will be read from “daftar.jsp” file,
<%@page import="com.edw.bean.Student"%>
<%@page import="java.io.ObjectInputStream"%>
<%@page import="java.io.File"%>
<%@page import="java.io.FileInputStream"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Daftar Nama</title>
</head>
<body>
<h1>Registered Name is : </h1>
<%
try{
FileInputStream fileInputStream = new FileInputStream(new File("D:\\test12.txt"));
ObjectInputStream objectInputStream = new ObjectInputStream(fileInputStream);
Student student = (Student)objectInputStream.readObject();
out.print("<h1>"+student.getName()+"</h1>");
}catch(Exception ex){
out.print(ex);
}
%>
</body>
</html>
Dont forget to register you servlet to web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>StudentServlet</servlet-name>
<servlet-class>com.edw.servlet.StudentServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>StudentServlet</servlet-name>
<url-pattern>/StudentServlet</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
Well it’s not too hard isnt it 😉
3 Comments
Manish Mishra
about 7 years agoIt's too easy to understand .
ReplyManish Mishra
about 7 years agoI am so sorry for "too easy to understand" . I want to say you it's really very easy.
Replyedwin
about 6 years agoHi Manish, glad it can help ;)