Programming

basic programming

How to Simulate JSon POST Request Using PHP and CURL

By / 18 December 2011 / PHP, Programming / , ,

Basically, im trying to do a PHP POST request using JSon string as its format and able to consume JSon array string as responses. Dont forget to activate CURL in your php.ini file.

<?php

//set POST variables address and json string
$url = 'http://localhost:81/dudu.php';
$fields = array(
		'userName'=>'yyy@xxx.com',
		'password'=>'yyyy',
		'emailProvider'=>'xxxx'
                );
//{"userName":"yyy@xxx.com","password":"yyyy","emailProvider":"xxxx"}

//url-ify the data for the JSON POST
$fields_string = json_encode($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_POST,count($fields));
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER , 1);

//execute post
$jsonResult = curl_exec($ch);

//close connection
curl_close($ch);

// [{"name":0,"email":"yyy@xxx.com"},{"name":1,"email":"yyy@xxx.com"},
// {"name":2,"email":"yyy@xxx.com"},{"name":3,"email":"yyy@xxx.com"}]
$results = json_decode($jsonResult, true);
foreach ( $results as $result )
{
    echo "name : {$result['name']} and email {$result['email']} <br />";
}

?>

This is what my browser will look like after im testing my JSon POST

Have fun with CURL 🙂

How to Handle JSon POST Request Using PHP

By / 16 December 2011 / PHP, Programming / , , ,

On my last project, i need to create a php service using JSon to handle service requests from multiple clients. My PHP file would consume JSon string for its requests and produce JSon string as its responses.
Im not too familiar with PHP, but after sometime googling i’ve found a workaround. This is how i do it.

<?php
// JSon request format is : 
// {"userName":"654321@zzzz.com","password":"12345","emailProvider":"zzzz"}

// read JSon input
$data_back = json_decode(file_get_contents('php://input'));

// set json string to php variables
$userName = $data_back->{"userName"};
$password = $data_back->{"password"};
$emailProvider = $data_back->{"emailProvider"};

// create json response
$responses = array();
for ($i = 0; $i < 10; $i++) {
    $responses[] = array("name" => $i, "email" => $userName . " " . $password . " " . $emailProvider);
}

// JSon response format is : 
// [{"name":"eeee","email":"eee@zzzzz.com"},
// {"name":"aaaa","email":"aaaaa@zzzzz.com"},{"name":"cccc","email":"bbb@zzzzz.com"}]

// set header as json
header("Content-type: application/json");

// send response
echo json_encode($responses);
?>

This is the http header and body of request and response.

Hope it help others, have fun with JSon. 😉

A Simple HTTPS Configuration Example on Apache Tomcat 6

By / 8 December 2011 / Java, Programming / , , ,

This idea comes suddenly on my head while i was reading a question on Kaskus’ programmer forum about how to setup a https connection on Apache Tomcat, thats why today im trying to write a simple how-to example on creating a simple HTTPS connection using Apache Tomcat 6. Who knows perhaps someone would find it useful.

Let’s start with creating a simple certificate file using keytool.exe 

C:\Program Files\Java\jdk1.6.0_19\bin>keytool.exe -genkey -alias tomcat -keyalg RSA -keystore edw.jks

after you insert your keystore password (i entered “secret” as my password) and several simple questions such as “What is your first and last name?”, it would create a file.

What you need to do next is to link your certificate to Tomcat’s server.xml configuration. This is what i add to my server.xml configuration.

<Connector port="8443" protocol="HTTP/1.1" SSLEnabled="true"
               maxThreads="150" scheme="https" secure="true"
               clientAuth="false" sslProtocol="TLS" keystoreFile="D:\edw.jks" 
               keystorePass="secret" />
<!-- keystorePass use the same password -->

And i also add this to my web.xml file, located under my tomcat’s conf folder 

	<security-constraint>
		<web-resource-collection>
			<web-resource-name>Automatic SLL Forwarding</web-resource-name>
			<url-pattern>/*</url-pattern>
		</web-resource-collection>
		<user-data-constraint>
			<transport-guarantee>CONFIDENTIAL</transport-guarantee>
		</user-data-constraint>
	</security-constraint>

This is what my page will look like,

Hope it would help others, cheers (B)

How to Create a Simple Servlet to Handle JSon Requests

By / 27 November 2011 / Java, Programming / , , , , ,

On this example, im trying to create a simple servlet to handle JSon request. Im using this servlet to handle JSon request from my front end such as web or even desktop application. Thanks to GSon library, it really helped on simplifying javabean convert to json strings and the other way around.

First as usual, a simple java bean to handle request and response format

package com.edw.bean;

public class Student {
 
    private String name;
    private int age;
    private byte gender;

	// other setter and getter
}

package com.edw.bean;

public class Status {
    private boolean success;
    private String description;
	
	// other setter and getter
}

And this is my servlet,

package com.edw.servlet;

import com.edw.bean.Status;
import com.edw.bean.Student;
import com.google.gson.Gson;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class JsonParserServlet extends HttpServlet {

    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("application/json");        
        Gson gson = new Gson();

        try {
            StringBuilder sb = new StringBuilder();
            String s;
            while ((s = request.getReader().readLine()) != null) {
                sb.append(s);
            }

            Student student = (Student) gson.fromJson(sb.toString(), Student.class);

            Status status = new Status();
            if (student.getName().equalsIgnoreCase("edw")) {
                status.setSuccess(true);
                status.setDescription("success");
            } else {
                status.setSuccess(false);
                status.setDescription("not edw");
            }
            response.getOutputStream().print(gson.toJson(status));
            response.getOutputStream().flush();
        } catch (Exception ex) {
            ex.printStackTrace();
            Status status = new Status();
            status.setSuccess(false);
            status.setDescription(ex.getMessage());
            response.getOutputStream().print(gson.toJson(status));
            response.getOutputStream().flush();
        } 
    }

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }
}

This is a screenshot on how my message actually look like

Have Fun (H)

Creating a Simple Yahoo Messenger Auto Response with Java and OpenYMSG Library

By / 5 March 2014 / Java, Programming / , ,

Hi, several days ago someone asked me to help him on his assignment related to Yahoo Messenger Application with Java. That’s why today im trying to help him by creating a simple example on auto response and message sending using one of the best open source Yahoo Messenger API implementation, OpenYMSG.

It’s actually quite easy, only several lines of codes. This is how i do it

package com.edw.yahoo;

import java.util.Scanner;
import org.apache.log4j.Logger;
import org.openymsg.network.FireEvent;
import org.openymsg.network.ServiceType;
import org.openymsg.network.Session;
import org.openymsg.network.event.SessionEvent;
import org.openymsg.network.event.SessionListener;

/**
 *  com.edw.yahoo.YahooLogin
 *
 *  @author edw
 */
public class YahooLogin implements SessionListener {

    private Logger logger = Logger.getLogger(YahooLogin.class);
    private Session session = new Session();

    public static void main(String[] args) {
        YahooLogin yahooLogin = new YahooLogin();
        yahooLogin.doLogin();
    }

    public YahooLogin() {
    }

    private void doLogin() {
        try {
            // insert your yahoo id
            // as for this example, im using my yahoo ID "dombaganas"
            session.login("dombaganas", "MyYahooPassword", true);
            session.addSessionListener(this);
            Scanner scanner = new Scanner(System.in);

            while (true) {
                System.out.println("please insert your message : ");
                String message = scanner.nextLine();

                // logout if message equals to "bye"
                if (message.equalsIgnoreCase("bye")) {
                    break;
                }
                // send message to targeted yahoo id
                session.sendMessage("TargetYahooID", message);
            }

            // logout from YM
            session.logout();
        } catch (Exception e) {
            logger.error(e, e);

        }
    }

    /*
     *  this is my listener method
     *  it listen for YM message request
     */
    @Override
    public void dispatch(FireEvent fe) {
        ServiceType type = fe.getType();
        SessionEvent sessionEvent = fe.getEvent();

        if (type == ServiceType.MESSAGE) {
            try {
                // log request message
                logger.debug("message from " + sessionEvent.getFrom() + " \nmessage " + sessionEvent.getMessage());

                // give an automatic response
                session.sendMessage(sessionEvent.getFrom(), "hi, you are sending " + sessionEvent.getMessage());
            } catch (Exception e) {
                logger.error(e, e);
            }
        }
    }
}

These are some screenshots related to this application.

To my friend, i hope this tutorial can help you getting started with your assignment. As the wise man once said “Answering one good question is like feeding a hungry person one meal, but teaching them research skills by example is showing them how to grow food for a lifetime.”

YNWA
(I)

ps. if somehow you found a NoClassDefFoundError, such as :
Exception in thread “main” java.lang.NoClassDefFoundError: org/apache/commons/logging/LogFactory
you need to include apache common logging lib into your project classpath.